/my/cssQuery/test.html - modified!

This page is modified from Dean Edwards' cssQuery test page. It's here for telling how are jQuery and cssQuery compatible with or different from each other. The background color of all "test" links should turn lime. If no, that means the rule above is failed to applied.

## cssQuery Test Page

### CSS Level 1

    #test1-1 p a {background-color: lime;}

This is a test link.

    #test1-2 :link {background-color: lime;}

This is a test link.

### CSS Level 2

    #test2-1 p.test.link a {background-color: lime;}

This is a test link.

    #test2-2 p > a {background-color: lime;}

This is a test link.

    #test2-3 span + a {background-color: lime;}

This is a test link.

    #test2-4 p:first-child a {background-color: lime;}

This is a test link.

    #test2-5 a:lang(en) {background-color: lime;}

This is a test link.

    #test2-6 a[href] {background-color: lime;}

This is a test link.

    #test2-7 a[title="This is a link"] {background-color: lime;}

This is a test link.

    #test2-8 a[title~="is"] {background-color: lime;}

This is a test link.

    div[id|=test2-9] a {background-color: lime;}

This is a test link.

### CSS Level 3

    #test3-1 span ~ a {background-color: lime;}

This is a test link.

    #test3-2 p:last-child a {background-color: lime;}

This is a test link.

    #test3-3 a:contains("test") {background-color: lime;}

This is a test link.

    #test3-4 p :not(span) {background-color: lime;}

This is a test link.

    #test3-5 p:only-child a {background-color: lime;}

This is a test link.

    #test3-6 p *:nth-child(even) {background-color: lime;}

This is a test link.

    #test3-7 p *:nth-last-child(2n+1) {background-color: lime;}

This is a test link.

    html:root #test3-8 a {background-color: lime;}

This is a test link.

    #test3-9 a[title^="This"] {background-color: lime;}

This is a test link.

    #test3-10 a[title*="is a"] {background-color: lime;}

This is a test link.

    #test3-11 a[title$="link"] {background-color: lime;}

This is a test link.