Software should be emi(exception safe): the program should continue to work
according to its specifications in the face of exceptions. It is not always
easy to realize exception safety. In this section some guidelines and
terminology is introduced when discussing exception safety.

Since exceptions may be generated from within all bf(C++) functions,
exceptions may be generated in many situations. Not all of these situations
are immediately and intuitively recognized as situations where exceptions can
be thrown. Consider the following function and ask yourself at which points
exceptions may be thrown:
        verb(    void fun()
    {
        X x;
        cout << x;
        X *xp = new X{ x };
        cout << (x + *xp);
        delete xp;
    })

If it can be assumed that tt(cout) as used above does not throw an
exception there are at least 13 opportunities for exceptions to be thrown:
    itemization(
    it() tt(X x): the default constructor could throw an exception (#1)
    it() tt(cout << x): the overloaded insertion operator could throw an
exception (#2), but its rhs argument might not be an tt(X) but, e.g., an
tt(int), and so tt(X::operator int() const) could be called which offers yet
another opportunity for an exception (#3).
    it() tt(*xp = new X{ x }): the copy constructor may throw an exception
(#4) and operator new (#5a) too. But did you realize that this latter
exception might not be thrown from tt(::new), but from, e.g., tt(X)'s own
overload of tt(operator new)? (#5b)
    it() tt(cout << (x + *xp)): we might be seduced into thinking that two
tt(X) objects are added. But it doesn't have to be that way. A separate class
Y might exist and tt(X) may have a conversion operator tt(operator Y() const),
and tt(operator+(Y const &lhs, X const &rhs), operator+(X const &lhs, Y const
&rhs)), and tt(operator+(X const &lhs, X const &rhs)) might all exist. So, if
the conversion operator exists, then depending on the kind of overload of
tt(operator+) that is defined either the addition's left-hand side operand
(#6), right-hand side operand (#7), or tt(operator+) itself (#8) may throw an
exception. The resulting value may again be of any type and so the overloaded
tt(cout << return-type-of-operator+) operator may throw an exception
(#9). Since tt(operator+) returns a temporary object it is destroyed shortly
after its use. tt(X)'s destructor em(could) throw an exception (#10).
    it() tt(delete xp): whenever tt(operator new) is overloaded tt(operator
delete) should be overloaded as well and may throw an exception (#11). And of
course, tt(X)'s destructor might again throw an exception (#12).
    it() tt(}): when the function terminates the local tt(x) object is
destroyed: again an exception could be thrown (#13).
        )
 It is stressed here (and further discussed in section ref(CONSEXCEPTIONS))
that although it is possible for exceptions to leave
destructors this would violate the bf(C++) standard and so it must be
prevented in well-behaving bf(C++) programs.

How can we expect to create working programs when exceptions might be thrown
in so many situations?

Exceptions may be generated in a great many situations, but serious
problems are prevented when we're able to provide at least one of the
following i(exception guarantees):
    itemization(
    it() The em(basic guarantee): no resources are leaked. In practice this
means: all allocated memory is properly returned when exceptions are thrown.
    it() The em(strong guarantee): the program's state remains unaltered when
an exception is thrown (as an example: the canonical form of the overloaded
assignment operator provides this guarantee)
    it() The em(nothrow) guarantee: this applies to code for which it can be
proven that no exception can be thrown from it.
    )
